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k-way hash collisions
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  • To: [EMAIL PROTECTED]
  • Subject: k-way hash collisions
  • From: kas kati <[EMAIL PROTECTED]>
  • Date: Wed, 8 Dec 2004 07:21:18 -0800 (PST)
  • Comment: DomainKeys? See http://antispam.yahoo.com/domainkeys
  • Domainkey-signature: a=rsa-sha1; q=dns; c=nofws; s=s1024; d=yahoo.com; b=nsrTpHUDqzavNxfu+9rgwGY8BUcGJ8vvI57QnyolPA00S+afGfhJEJPudJYu/cPQefKxQdGjCCI7bOs9Rmwo2zv+lvzUVIFM8Vq4B0g1NQyLRbnYUGTlOUtRzkFflhKje0ojXCeObqd7eD++yOyuhscLi1Dq7MPeiddm4hemzGM= ;
  • Sender: [EMAIL PROTECTED]
.
 
For an ideal hash function, the complexity of finding a k-way
collision is
O(2^{(k-1)n/k}) therefore as k becomes larger, the complexity of a
k-way collision attack approaches the complexity of a pre-image
attack.

Recently, Joux showed a generic multi-collision attack for iterated
hash functions to reduce the k-way collision complexity to
O(log(k)*2^{(n/2)}). But in his attack the pre-images are not
independent. They are just combinations of block collisions of k
blocks. Here are my questions:

1. How can the formula for the complexity of finding a k-way collision
be derived?

2. Is there any hash design that allows to reduce the complexity of
k-way collision for "independent" pre-images while preserving the
complexity of the pre-image attack?

Thanks in advance for your interest.



		
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